Distance, Speed & Time

Junior Cycle Higher Level Mathematics revision notes with diagrams, key terms and self-check questions.

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Speed tells us how far something travels in a given time. Exam questions involve calculating distance, speed, and time, converting units, and drawing or interpreting journey graphs.

Core Formulas and Rearranging

Speed measures how quickly an object covers distance. All calculations connect through the formula d=std = st, where dd is distance, ss is speed, and tt is time.

At Higher Level, change the subject of the formula using algebra rather than relying on formula triangles:

  • To find distance: d=std = st
  • To find speed: divide both sides by tt to get s=dts = \frac{d}{t}
  • To find time: divide both sides by ss to get t=dst = \frac{d}{s}

Proportionality connects these variables directly:

  • At a constant speed, distance is directly proportional to time: double the time means double the distance.
  • For a fixed distance, speed and time are inversely proportional: double the speed means half the time.

Units, Conversions, and Accuracy

Units must match before substituting values into any formula. Standard pairs are kilometres with hours (km/h\text{km/h}) and metres with seconds (m/s\text{m/s}).

To convert units:

  • Hours and minutes to hours: divide the minutes by 6060. For example, 1 h 40 min=1+4060=53 hours1\text{ h } 40\text{ min} = 1 + \frac{40}{60} = \frac{5}{3}\text{ hours}. Keep awkward decimals as fractions so you do not lose accuracy.
  • km/h\text{km/h} to m/s\text{m/s}: multiply by 10001000 and divide by 36003600 (or divide by 3.63.6). For example, 90 km/h=90×10003600=25 m/s90\text{ km/h} = \frac{90 \times 1000}{3600} = 25\text{ m/s}.
  • m/s\text{m/s} to km/h\text{km/h}: multiply by 36003600 and divide by 10001000 (or multiply by 3.63.6). For example, 20 m/s=20×3.6=72 km/h20\text{ m/s} = 20 \times 3.6 = 72\text{ km/h}.
  • Speed per second to speed per minute: multiply by 6060.

Keep full calculator accuracy during working, write the required unit, and round only at the end to the requested accuracy or scientific notation a×10na \times 10^n.

Average Speed for Multi-Stage Journeys

For any multi-stage journey, average speed is calculated using overall totals:

Average Speed=Total DistanceTotal Time\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}

Averaging stage speeds generally gives the wrong answer. If you travel two stages of equal distance at different speeds, you spend longer travelling at the slower speed, so the slow part counts for more of the total journey time.

For example, driving 60 km60\text{ km} at 60 km/h60\text{ km/h} takes 1 hour1\text{ hour}, and driving another 60 km60\text{ km} at 30 km/h30\text{ km/h} takes 2 hours2\text{ hours}. The total distance is 120 km120\text{ km} and the total time is 3 hours3\text{ hours}. The average speed is 1203=40 km/h\frac{120}{3} = 40\text{ km/h}, not the arithmetic mean of 45 km/h45\text{ km/h}.

Drawing and Interpreting Distance–Time Graphs

Always check axis labels and units first. With time horizontally and total distance travelled vertically, slope gives speed: change in distance ÷ change in time.

Distance–time graph with a steeper section A and a shallower section B. Dashed triangles show the distance and time changes for each section.
Distance–time graph with a steeper section A and a shallower section B. Dashed triangles show the distance and time changes for each section.

Key graph rules:

  • A steeper line means a faster speed.
  • A flat, horizontal segment means the object is stationary (speed is zero).
  • Distance travelled can never decrease. On a distance-from-home graph, a downward segment shows returning home. For travel along a straight route towards or away from home, speed is the positive size of the slope.
  • On a distance-from-home graph, the intercept shows starting distance, the highest point shows greatest distance, and zero means home.
Two schematic graphs show the same outward journey, stop and return. Total distance rises again during the return, while distance from home falls to zero.
Two schematic graphs show the same outward journey, stop and return. Total distance rises again during the return, while distance from home falls to zero.

To draw a graph:

  • Label axes with quantities and units, using an even scale.
  • Plot the coordinates for each time–distance pair.
  • Join points with straight segments for periods of constant speed.

Key terms

Speed
The distance travelled per unit of time, calculated as s=dts = \frac{d}{t} and measured in units such as km/h\text{km/h} or m/s\text{m/s}.
Average Speed
The total distance travelled divided by the total elapsed time for an entire journey, including any stops.
Constant Speed
Motion where the rate of travel does not change, shown by a straight line segment on a distance–time graph.
Stationary
The state of being at rest, represented on a distance–time graph by a horizontal line segment with a slope of zero.
Slope (rate of change)
Vertical change ÷ horizontal change; with time horizontally and total distance travelled vertically, slope gives speed.

Check yourself

  1. Rearrange d = st to express time t in terms of d and s.

    Divide both sides by s to get t = d/s.

  2. Convert a speed of 25 m/s into km/h.

    25 × 3.6 = 90 km/h.

  3. For a fixed journey distance, how does tripling the speed affect the travel time?

    Travel time is divided by 3 (one-third as long) because speed and time are inversely proportional.

  4. A distance–time graph has points plotted at (0, 0), (10, 1), and (15, 1), with time in minutes and distance in km. Describe the motion.

    The traveller covers 1 km in the first 10 minutes, then remains stationary for 5 minutes.

  5. A runner covers 60 m in 30 s and then 150 m in 20 s. What is their average speed?

    Total distance is 210 m and total time is 50 s, giving an average speed of 210 / 50 = 4.2 m/s.

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