Algebra - Factorising

Junior Cycle Higher Level Mathematics revision notes with diagrams, key terms and self-check questions.

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Factorising rewrites an expanded algebraic expression as a multiplication of its factors. For Junior Cycle Higher Level, the exam tests your ability to spot common factors, group terms in pairs, factorise quadratic trinomials, and apply the difference of two squares.

Highest Common Factor

Always check for a common factor before trying any other method.

  • Find the largest whole number that divides into every coefficient.
  • Pick each shared letter at its lowest power.
  • Place this highest common factor outside a single bracket.
  • Divide every original term by this factor to find what stays inside.
ExpressionHighest Common FactorFactorised Form
6x2−9x6x^2 - 9x3x3x3x(2x−3)3x(2x - 3)
10xy+15yz10xy + 15yz5y5y5y(2x+3z)5y(2x + 3z)
4ab2−8a2b4ab^2 - 8a^2b4ab4ab4ab(b−2a)4ab(b - 2a)

When a term divides out completely, write 11 in the bracket as its placeholder. For example, 4x+44x + 4 factors as 4(x+1)4(x + 1) rather than leaving a gap.

Grouping in Pairs

For suitable four-term expressions, grouping can reveal a shared factor.

  • Group terms into two pairs that each contain a common factor.
  • Take the highest common factor out of the first pair.
  • Factorise the second pair so its bracket matches the first exactly.
  • Pull that identical bracket out to finish the factorisation.

Watch your signs when pulling out a negative number: −5x−15-5x - 15 becomes −5(x+3)-5(x + 3).

Difference of Two Squares

Spot this pattern whenever two square terms are separated by a minus sign: A2−B2=(A−B)(A+B)A^2 - B^2 = (A - B)(A + B).

A square of side A with a corner square of side B removed is rearranged into a rectangle with sides A − B and A + B.
A square of side A with a corner square of side B removed is rearranged into a rectangle with sides A − B and A + B.
  • Write each term as a square to identify AA and BB.
  • Write the factors into two brackets, using a minus in one and a plus in the other.
  • At Higher Level, questions often include coefficients on both terms, like a2x2−b2y2a^2x^2 - b^2y^2.

For example, 25x2=(5x)225x^2 = (5x)^2 and 49y2=(7y)249y^2 = (7y)^2, so 25x2−49y2=(5x−7y)(5x+7y)25x^2 - 49y^2 = (5x - 7y)(5x + 7y). An expression with a plus sign, like x2+25x^2 + 25, is not a difference and cannot be factorised using real numbers.

Quadratic Trinomials

Trinomials take the form ax2+bx+cax^2 + bx + c, where the value of aa decides your approach.

  • For monic quadratics where a=1a = 1, find two integers that multiply to give cc and add to give bb.
  • For x2−10x+21x^2 - 10x + 21, the numbers −7-7 and −3-3 work, giving (x−7)(x−3)(x - 7)(x - 3).
  • When a>1a > 1, calculate the product acac first.
  • Find two integers that multiply to acac and add to the middle coefficient bb.
  • Split the middle term into these two values and factorise by grouping.

See the worked example below for a step-by-step walkthrough of factorising when a>1a > 1.

Key terms

Factor
A number or algebraic expression that divides evenly into another without leaving a remainder.
Highest Common Factor (HCF)
The greatest term consisting of numbers and variables that divides into every term of an expression.
Factorising by Grouping
A method for four-term expressions that pairs terms to pull out a shared binomial bracket.
Difference of Two Squares
A binomial pattern A2−B2A^2 - B^2 which splits into the product (A−B)(A+B)(A - B)(A + B).
Quadratic Trinomial
A three-term expression of the form ax2+bx+cax^2 + bx + c, where a≠0a \neq 0.

Check yourself

  1. What is the completely factorised form of 12a2b−8ab212a^2b - 8ab^2?

    4ab(3a−2b)4ab(3a - 2b)

  2. Factorise the difference of squares 36x2−49y236x^2 - 49y^2.

    (6x−7y)(6x+7y)(6x - 7y)(6x + 7y)

  3. Factorise x2−9x+20x^2 - 9x + 20.

    (x−4)(x−5)(x - 4)(x - 5), since (−4)×(−5)=20(-4) \times (-5) = 20 and (−4)+(−5)=−9(-4) + (-5) = -9.

  4. Factorise ab−3a+2b−6ab - 3a + 2b - 6 using grouping.

    (a+2)(b−3)(a + 2)(b - 3), since a(b−3)+2(b−3)=(a+2)(b−3)a(b - 3) + 2(b - 3) = (a + 2)(b - 3).

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