Constructions

Junior Cycle Higher Level Mathematics revision notes with diagrams, key terms and self-check questions.

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Geometric constructions use instruments to draw shapes, lines, and angles accurately. In the Junior Cycle Higher Level exam, you must carry out constructions 1 to 15 accurately, and sometimes name the theorem that makes the construction work.

The Five Allowed Instruments

To construct means to draw accurately using only the approved tools, rather than sketching freehand.

  • Straight-edge: rules a straight line through two points without measuring length.
  • Compass: draws circles or arcs and marks off equal lengths.
  • Ruler: measures lengths in centimetres and millimetres, and marks a point at a given distance along a ray.
  • Protractor: measures an angle, and marks a ray making a given number of degrees with another ray.
  • Set-squares: draw 90°, 45°, 30°, and 60° angles, or slide along a ruler to draw parallel lines.

Always use a sharp pencil.

Lines, Bisectors, and Perpendiculars (Constructions 1–5)

These constructions create right angles, bisect angles and segments, or draw parallel lines.

No.ConstructionTools for this methodKey Step
1Angle bisectorCompass and straight-edge onlyDraw an arc across both arms; from crossings, draw equal intersecting arcs; rule ray.
2Perpendicular bisector of [AB]Compass and straight-edge onlyKeep the same radius, greater than half AB; draw arcs from both ends and join their two crossings.
3 (HL)Perpendicular to line through external pointCompass, straight-edgeArc from point cuts line twice; draw equal arcs from crossings; join intersections through point.
4Perpendicular to line through point on lineCompass, straight-edgeMark equal arcs either side of point; construct perpendicular bisector of that segment.
5Line parallel to line through given pointRuler, set-squareAlign set-square to line, place ruler on edge, slide set-square to point, rule line.
An arc centred at O cuts the angle’s arms at X and Y. Equal-radius arcs from X and Y meet at P; ray OP bisects the angle.
An arc centred at O cuts the angle’s arms at X and Y. Equal-radius arcs from X and Y meet at P; ray OP bisects the angle.
An arc from P crosses line l at X and Y. Equal-radius arcs from X and Y meet at Q across the line. PQ is perpendicular to l.
An arc from P crosses line l at X and Y. Equal-radius arcs from X and Y meet at Q across the line. PQ is perpendicular to l.

Dividing Segments, Rays, and Angles (Constructions 6–9)

Constructions 6 and 7 divide a segment into equal parts without measuring with a ruler.

  • Draw a ray from one end of the segment at an acute angle.
  • For Construction 6, use a compass to mark 2 or 3 equal steps along the ray.
  • For Construction 7 (HL only), mark any required number n of equal steps.
  • Join the last step mark to the other end of the segment.
  • Using a sliding set-square, draw lines parallel to this join through each step mark.

This method works because parallel lines that cut off equal segments on one transversal line cut off equal segments on any other transversal line (Theorem 11).

Three equal compass steps along an auxiliary ray are transferred to segment AB using parallel joins, dividing AB into thirds.
Three equal compass steps along an auxiliary ray are transferred to segment AB using parallel joins, dividing AB into thirds.

For Construction 8, measure a given length along a ray. For Construction 9, centre a protractor at the vertex, align the zero line, mark the required angle, and draw a ray from the vertex through the mark.

Triangles and Rectangles (Constructions 10–15)

Triangles and rectangles are constructed from given sides, angles, or right angles.

No.GivenMethod
10SSS: three sidesShorter sides must total more than longest. Draw base; remaining lengths set endpoint arcs. Join crossing to endpoints.
11SAS: two sides, angle betweenDraw angle; mark lengths on arms; join.
12ASA: two angles, side betweenDraw side; construct endpoint angles on same side; rays meet.
13RHS: right angle, hypotenuse, sideDraw leg AB; perpendicular at B. Arc centred A, hypotenuse radius, locates C; join AC.
14∠A=α, ∠B=90°AB given: perpendicular at B meets α ray from A. BC given: perpendicular at B meets (90°−α) ray from C. AC given: α and (90°−α) rays at A and C meet on same side.
15Rectangle: side lengthsDraw base; perpendicular sides of required length on same side; join tops.
A scalene triangle ABC constructed on base AB, with arcs centred at A and B crossing at C.
A scalene triangle ABC constructed on base AB, with arcs centred at A and B crossing at C.
A perpendicular at B meets an arc centred at A at C, forming triangle ABC with hypotenuse AC.
A perpendicular at B meets an arc centred at A at C, forming triangle ABC with hypotenuse AC.

Key terms

Construct
To use properties of shapes and geometric results to draw accurately, using only the prescribed geometrical tools.
Sketch
To draw a rough diagram or graph without using geometrical tools.
Straight-edge
An ungraduated instrument used solely with a pencil to draw a straight line passing through two marked points.
Angle bisector
A ray that divides an angle into two angles of equal measure.
Perpendicular bisector
The straight line through the midpoint of a segment that is perpendicular to that segment.
Hypotenuse
The side opposite the right angle in a right-angled triangle.
Transversal
A line that intersects two or more other lines.

Check yourself

  1. Which two constructions from 1 to 15 are examinable at Higher Level only?

    Construction 3 (perpendicular to a line through an external point) and Construction 7 (dividing a segment into any number of equal parts without measuring).

  2. An angle bisector divides an angle measuring 74°. What is the measure of each resulting angle?

    37°, because 74° ÷ 2 = 37°.

  3. Which theorem explains why dividing a line segment using a helper ray and parallel lines works?

    Theorem 11: if three parallel lines cut off equal segments on some transversal line, then they will cut off equal segments on any other transversal.

  4. Why can a triangle not be constructed with side lengths 3 cm, 4 cm, and 8 cm?

    Because 3 cm + 4 cm = 7 cm, which is less than 8 cm; the two shorter sides together are not longer than the third side, so the arcs cannot cross.

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