Algebra - Cubics

Leaving Cert Higher Level Mathematics revision notes.

3 min readHigher LevelBy Studytok
Practise this topic — free →

The Factor Theorem and Cubic Equations

The Factor Theorem establishes that a polynomial P(x)P(x) has a factor (x−k)(x - k) if and only if P(k)=0P(k) = 0. Conversely, if P(k)=0P(k) = 0, then x=kx = k is a root of the polynomial equation P(x)=0P(x) = 0. Exam cubics usually have at least one integer root. If a cubic with integer coefficients has an integer root, that root must be a factor of the constant term, so test those factors (positive and negative) first.

To solve a cubic equation like 2x3−3x2−17x+30=02x^3 - 3x^2 - 17x + 30 = 0, begin by testing integer factors of 3030, such as ±1,±2,±3\pm 1, \pm 2, \pm 3. Evaluating P(−3)P(-3) gives 2(−27)−3(9)−17(−3)+30=−54−27+51+30=02(-27) - 3(9) - 17(-3) + 30 = -54 - 27 + 51 + 30 = 0. Because P(−3)=0P(-3) = 0, (x+3)(x + 3) is a factor.

Next, divide the cubic polynomial by (x+3)(x + 3) using algebraic long division. This division yields the quadratic quotient 2x2−9x+102x^2 - 9x + 10. Factoring the quadratic gives (2x−5)(x−2)(2x - 5)(x - 2). Setting each factor to zero provides the complete set of roots: x=−3x = -3, x=2x = 2, and x=52x = \frac{5}{2}.

You've read the theory
Now turn it into exam marks.

Practise algebra - cubics as questions and flashcards in Studytok, with explanations when you get stuck.

Continue for free →
  1. ✓
    Read the notes
    1 sections
  2. 2
    Test yourself
    Questions marked instantly
  3. 3
    Keep revising
    Flashcards and exam-style practice