Acid-Base Titrations

Everything you need for Leaving Cert Higher Level Chemistry — syllabus-aligned explanations, key terms and self-check questions.

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Volumetric analysis determines the concentration of an unknown solution by reacting it completely with a standard solution of known concentration. In acid-base titrations, we match stoichiometric mole ratios from balanced equations with sharp indicator colour changes to measure reacting volumes with high precision. The Leaving Certificate Chemistry course requires five mandatory practicals: preparing a standard sodium carbonate solution, standardising hydrochloric acid, standardising sodium hydroxide, determining the ethanoic acid concentration of vinegar, and calculating the water of crystallisation in washing soda.

The Five Mandatory Titrations and Primary Standards

Every acid-base titration question in Section A stems from five core practicals:

  1. Preparation of a standard solution of sodium carbonate.
  2. Standardisation of a hydrochloric acid solution using standard sodium carbonate.
  3. Standardisation of a sodium hydroxide solution using standard hydrochloric acid.
  4. Determination of the concentration of ethanoic acid in commercial vinegar.
  5. Determination of the water of crystallisation in hydrated sodium carbonate (washing soda).

A standard solution is a solution of accurately known concentration. When we make one directly by weighing out a solid and dissolving it to a known volume, that solid must be a primary standard.

A primary standard is a substance that can be obtained in a pure, stable form, of known formula, so that a standard solution can be made by weighing it out accurately and dissolving it in a known volume of water. To work on the balance, it must satisfy strict criteria:

  • High purity: it is available in a very pure state (at least 99.9% pure), so the mass weighed out is effectively all target substance.
  • Stability: it does not decompose or react with gases in the air.
  • Known chemical formula: its relative formula mass can be calculated with certainty.
  • Non-hygroscopic: it does not absorb water vapour from the air, which would add unmeasured water weight.
  • High relative molar mass: a larger mass must be weighed out on the balance, making the percentage weighing error significantly smaller.
  • Solubility: it dissolves completely in water and reacts according to a single, known balanced equation.

Anhydrous sodium carbonate (Na2CO3\text{Na}_2\text{CO}_3, relative formula mass 106, molar mass M=106 g mol−1M = 106\text{ g mol}^{-1}) is the primary standard for acid-base work. Hydrated sodium carbonate can also serve if weighed rapidly, because the crystals are efflorescent (they lose water of crystallisation to dry air). Other accepted primary standards across the Leaving Certificate include ammonium iron(II) sulfate, potassium dichromate, ethanedioic acid (oxalic acid), and potassium hydrogenphthalate.

Substances that fail these criteria cannot be weighed out directly. Solid sodium hydroxide is deliquescent; it absorbs atmospheric moisture so rapidly that it dissolves in the absorbed water, and it also absorbs carbon dioxide gas. Concentrated hydrochloric acid fumes constantly, losing hydrogen chloride gas and allowing its concentration to drift. We prepare approximate solutions of both and standardise them experimentally.

Preparing a Standard Sodium Carbonate Solution (250 cm³)

  1. Accurately weigh roughly 2.65 g2.65\text{ g} of anhydrous Na2CO3\text{Na}_2\text{CO}_3 on a clean clock glass using an electronic balance reading to at least 0.001 g0.001\text{ g}.
  2. Transfer the solid into a beaker containing about 100 cm3100\text{ cm}^3 of deionised water. Rinse the clock glass with deionised water into the beaker using a wash bottle so that no solute particles remain on the glass.
  3. Stir with a clean glass rod until all crystals dissolve completely.
  4. Pour the solution through a clean glass funnel into a 250 cm3250\text{ cm}^3 volumetric flask. Rinse the beaker, glass rod, and funnel with deionised water from the wash bottle, draining all washings into the volumetric flask (a quantitative transfer).
  5. Add deionised water until the level is just below the graduation mark on the neck.
  6. With your eye level with the mark to eliminate parallax error, use a dropper to add deionised water dropwise until the bottom of the meniscus rests exactly on the graduation mark.
  7. Stopper the flask firmly, hold the stopper securely, and invert the flask about 20 times to achieve complete mixing and a uniform concentration.

Volumetric Apparatus, Rinsing Rules, and Titration Setup

Accurate and concordant titres depend on rinsing each piece of glassware correctly before use. Rinsing errors systematically shift your recorded volumes.

GlasswarePreparation and Rinsing RoutineExaminer Reasoning
PipetteRinse with deionised water, then with the solution it will deliverWater removes previous chemical residues; rinsing with the solution removes remaining water droplets that would otherwise dilute the delivered sample and lower the moles transferred.
BuretteRinse with deionised water, then with the titrant it will deliverWater cleans the barrel; rinsing with titrant prevents residual water droplets from diluting the titrant, which would artificially inflate the required titre volume.
Conical FlaskRinse with deionised water onlyRinsing with the solution leaves unmeasured droplets of solute in the flask, adding extra moles and causing experimental error.
Volumetric FlaskRinse with deionised water onlyResidual deionised water becomes part of the final solvent volume when the flask is filled to the graduation mark.

Describing and Drawing the Titration Set-Up

When asked to draw or describe the titration apparatus, include:

  • A burette clamped vertically in a burette clamp attached to a retort stand.
  • The stopcock (tap) positioned near the bottom, with a narrow jet below it completely filled with liquid and free of air bubbles.
  • A conical flask positioned beneath the burette jet, resting on a white tile to make the first permanent colour change easy to see.
  • Burette contents clearly labelled (for example, 'HCl\text{HCl} solution of unknown concentration') and conical flask contents clearly labelled (for example, '25.0 cm325.0\text{ cm}^3 standard Na2CO3\text{Na}_2\text{CO}_3 solution + 2–3 drops methyl orange').
  • Associated measuring tools: a 25 cm325\text{ cm}^3 pipette fitted with a safety pipette filler, and a 250 cm3250\text{ cm}^3 volumetric flask with a stopper and single graduation mark on its narrow neck.

Filling the Burette and Removing Air Bubbles

Fill the burette using a clean funnel, but remove the funnel immediately after filling. If left in place, drops hanging on the funnel stem can fall into the burette during the titration, making the recorded titre artificially low. Open the tap fully into a waste beaker to fill the narrow jet below the tap and expel any trapped air bubble. If an air bubble dislodges during the titration run, the burette reading drops without that volume entering the flask, making the recorded titre too high.

Meniscus Alignment and Reading Precision

For colourless and pale solutions, read the bottom of the curved meniscus at eye level to eliminate parallax error. For intensely coloured solutions where the bottom is obscured (such as potassium manganate(VII)), read the top of the meniscus, using the identical point for both initial and final readings.

A burette is graduated in 0.1 cm30.1\text{ cm}^3 divisions and read to the nearest 0.05 cm30.05\text{ cm}^3. Record all readings to two decimal places ending in .00.00 or .05.05 (for example, 23.45 cm323.45\text{ cm}^3). Because a titre requires two readings (initial and final), each reading carries an uncertainty of ±0.05 cm3\pm0.05\text{ cm}^3, giving a combined reading uncertainty of ±0.1 cm3\pm0.1\text{ cm}^3.

A 25 cm325\text{ cm}^3 pipette delivers one fixed volume with an uncertainty of about ±0.06 cm3\pm0.06\text{ cm}^3, compared to roughly ±0.5 cm3\pm0.5\text{ cm}^3 for a graduated cylinder. A pipette is calibrated to deliver: drain it under gravity, touch the jet tip against the inside neck of the conical flask, and leave the tiny drop trapped in the tip. Never blow that final drop out, or the delivered volume will be too large.

Recording Results and Concordancy

Perform one rough titration to find the approximate end point, followed by accurate runs where titrant is added drop by drop with continuous swirling near the colour change. Accompany each run by rinsing down the inner walls of the conical flask with deionised water; this washes splashed reagents into the mixture without altering the total moles present.

Accurate titres that agree within 0.1 cm30.1\text{ cm}^3 are concordant. Discard the rough run and average only the concordant values:

RunRough123
Final reading (cm3\text{cm}^3)23.9023.4523.5023.45
Initial reading (cm3\text{cm}^3)0.000.000.050.00
Titre (cm3\text{cm}^3)23.9023.4523.4523.45

Average titre = (23.45+23.45+23.45)÷3=23.45 cm3(23.45 + 23.45 + 23.45) \div 3 = 23.45\text{ cm}^3.

Titration Curves, Indicator Theory, and pH Calculations

An acid-base indicator is a weak acid in which the un-ionised molecule (HIn\text{HIn}) exhibits a different colour from its conjugate base (In−\text{In}^-):

HIn(aq)⇌H+(aq)+In−(aq)\text{HIn}(aq) \rightleftharpoons \text{H}^+(aq) + \text{In}^-(aq)(Colour A)⇌(Colour B)\text{(Colour A)} \rightleftharpoons \text{(Colour B)}

In acidic solutions, high [H+][\text{H}^+] shifts the position of equilibrium to the left by Le Châtelier's principle, showing Colour A. Adding base removes H+\text{H}^+ ions, pulling the equilibrium to the right and showing Colour B.

The equivalence point represents the stage where stoichiometric amounts of acid and base have reacted in the exact ratio given by the balanced equation. The end point is the stage where the indicator permanently changes colour. An indicator is suitable only when its colour-change pH interval lies entirely within the vertical, steep section of the titration curve.

Titration CombinationStarting pHpH Range of Steep SectionpH at Equivalence PointSuitable Indicator
Strong acid – Strong base (HCl\text{HCl} vs NaOH\text{NaOH})~13 to 117.0 (neutral salt)Methyl orange (3.1–4.4) or phenolphthalein (8.2–10.0)
Weak acid – Strong base (CH3COOH\text{CH}_3\text{COOH} vs NaOH\text{NaOH})~2.97 to 11Above 7 (~8.7)Phenolphthalein only
Strong acid – Weak base (HCl\text{HCl} vs Na2CO3\text{Na}_2\text{CO}_3 or NH3\text{NH}_3)~13 to 7Below 7 (~4 to 5)Methyl orange only
Weak acid – Weak base~2.9No steep vertical jump~7None (use a pH meter or conductivity probe)

Why the Equivalence pH is Not Always 7

The salt produced during neutralisation can hydrolyse with water. In a vinegar titration, sodium ethanoate dissociates into ethanoate ions (CH3COO−\text{CH}_3\text{COO}^-). These act as a Brønsted-Lowry base, accepting protons from water:

CH3COO−+H2O⇌CH3COOH+OH−\text{CH}_3\text{COO}^- + \text{H}_2\text{O} \rightleftharpoons \text{CH}_3\text{COOH} + \text{OH}^-

This generation of OH−\text{OH}^- makes the equivalence solution alkaline (pH ~8.7). Phenolphthalein changes colour between pH 8.2 and 10.0, sitting directly across this jump, whereas methyl orange changes between 3.1 and 4.4 and would change long before the equivalence point is reached.

Acid-Base Definitions and pH Relationships

  • Brønsted-Lowry acid: a substance that donates a proton (H+\text{H}^+).
  • Brønsted-Lowry base: a substance that accepts a proton.
  • Conjugate acid-base pair: two chemical species that differ by a single proton. In CH3COOH+H2O⇌CH3COO−+H3O+\text{CH}_3\text{COOH} + \text{H}_2\text{O} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}_3\text{O}^+, the conjugate pairs are CH3COOH/CH3COO−\text{CH}_3\text{COOH} / \text{CH}_3\text{COO}^- and H3O+/H2O\text{H}_3\text{O}^+ / \text{H}_2\text{O}.
  • Strong vs Weak: A strong acid or base dissociates completely in water (such as HCl\text{HCl} or NaOH\text{NaOH}). A weak acid or base dissociates only partially in water (such as CH3COOH\text{CH}_3\text{COOH} or NH3\text{NH}_3).
  • Concentrated vs Dilute: 'Concentrated' refers to a high amount of solute per litre of solution; 'strong' refers strictly to the degree of dissociation. Ethanoic acid can be concentrated, but it is always weak.
  • Amphoteric: a substance capable of acting as either an acid or a base (such as H2O\text{H}_2\text{O}).

Key mathematical relationships:

pH=−log⁡10[H3O+]and[H3O+]=10−pH\text{pH} = -\log_{10}[\text{H}_3\text{O}^+] \quad \text{and} \quad [\text{H}_3\text{O}^+] = 10^{-\text{pH}}Kw=[H3O+][OH−]=1.0×10−14 mol2 l−2 at 25 ∘CK_w = [\text{H}_3\text{O}^+][\text{OH}^-] = 1.0 \times 10^{-14}\text{ mol}^2\text{ l}^{-2}\text{ at }25\text{ }^\circ\text{C}
  • For 0.100 mol l−1 HCl0.100\text{ mol l}^{-1}\text{ HCl}: [H3O+]=0.100 mol l−1⇒pH=−log⁡(0.100)=1.00[\text{H}_3\text{O}^+] = 0.100\text{ mol l}^{-1} \Rightarrow \text{pH} = -\log(0.100) = 1.00.
  • For 0.100 mol l−1 NaOH0.100\text{ mol l}^{-1}\text{ NaOH}: [OH−]=0.100 mol l−1⇒[H3O+]=1.0×10−14÷0.100=1.0×10−13 mol l−1⇒pH=13.00[\text{OH}^-] = 0.100\text{ mol l}^{-1} \Rightarrow [\text{H}_3\text{O}^+] = 1.0 \times 10^{-14} \div 0.100 = 1.0 \times 10^{-13}\text{ mol l}^{-1} \Rightarrow \text{pH} = 13.00.
  • For a weak acid where Ka=[H3O+][A−][HA]K_a = \frac{[\text{H}_3\text{O}^+][\text{A}^-]}{[\text{HA}]}: [H3O+]=Ka×c[\text{H}_3\text{O}^+] = \sqrt{K_a \times c}. For 0.100 mol l−10.100\text{ mol l}^{-1} ethanoic acid (Ka=1.8×10−5K_a = 1.8 \times 10^{-5}), [H3O+]=1.8×10−5×0.100=1.34×10−3 mol l−1⇒pH=2.87[\text{H}_3\text{O}^+] = \sqrt{1.8 \times 10^{-5} \times 0.100} = 1.34 \times 10^{-3}\text{ mol l}^{-1} \Rightarrow \text{pH} = 2.87.

Mandatory Experiments: Standardising Acids and Bases

Volumetric calculations rely on stoichiometric ratios established by the balanced chemical equation.

ReactionBalanced Chemical EquationMole Ratio (Acid : Base)
HCl+NaOH\text{HCl} + \text{NaOH}HCl+NaOH→NaCl+H2O\text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O}1:11 : 1
HCl+Na2CO3\text{HCl} + \text{Na}_2\text{CO}_32HCl+Na2CO3→2NaCl+H2O+CO22\text{HCl} + \text{Na}_2\text{CO}_3 \rightarrow 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_22:12 : 1
HCl+NH3\text{HCl} + \text{NH}_3HCl+NH3→NH4Cl\text{HCl} + \text{NH}_3 \rightarrow \text{NH}_4\text{Cl}1:11 : 1
CH3COOH+NaOH\text{CH}_3\text{COOH} + \text{NaOH}CH3COOH+NaOH→CH3COONa+H2O\text{CH}_3\text{COOH} + \text{NaOH} \rightarrow \text{CH}_3\text{COONa} + \text{H}_2\text{O}1:11 : 1
H2SO4+NaOH\text{H}_2\text{SO}_4 + \text{NaOH}H2SO4+2NaOH→Na2SO4+2H2O\text{H}_2\text{SO}_4 + 2\text{NaOH} \rightarrow \text{Na}_2\text{SO}_4 + 2\text{H}_2\text{O}1:21 : 2
(COOH)2+NaOH(\text{COOH})_2 + \text{NaOH}(COOH)2+2NaOH→(COONa)2+2H2O(\text{COOH})_2 + 2\text{NaOH} \rightarrow (\text{COONa})_2 + 2\text{H}_2\text{O}1:21 : 2

A diprotic acid or a metal carbonate always introduces a factor of 2 into the mole ratio.

Mandatory Practical 1 & 2: Standardising Hydrochloric Acid

  • Purpose: to determine the accurate concentration of an approximate bench HCl\text{HCl} solution using primary standard Na2CO3\text{Na}_2\text{CO}_3.
  • Apparatus: 50.0 cm350.0\text{ cm}^3 burette, 25.0 cm325.0\text{ cm}^3 pipette with filler, 250 cm3250\text{ cm}^3 conical flask, white tile, wash bottle.
  • Stoichiometry: Na2CO3+2HCl→2NaCl+H2O+CO2\text{Na}_2\text{CO}_3 + 2\text{HCl} \rightarrow 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_2 (ratio 1:21 : 2).
  • Method:
  1. Pipette exactly 25.0 cm325.0\text{ cm}^3 of standard 0.050 mol l−1 Na2CO30.050\text{ mol l}^{-1}\text{ Na}_2\text{CO}_3 solution into a conical flask previously rinsed with deionised water.
  2. Add 2 to 3 drops of methyl orange indicator; the mixture turns yellow.
  3. Fill the burette with HCl\text{HCl} after rinsing with deionised water and titrant; expel the jet air bubble and adjust to 0.00 cm30.00\text{ cm}^3.
  4. Titrate over a white tile, swirling continuously and washing down flask walls with deionised water.
  5. Near the end point, add HCl\text{HCl} dropwise until one drop causes a permanent colour change from yellow to pink/red.
  6. Repeat to obtain concordant titres within 0.1 cm30.1\text{ cm}^3 and calculate their average.
  • Gas testing: Effervescence occurs during titration due to CO2\text{CO}_2 gas. Bubbling this gas through limewater turns the limewater milky/cloudy due to CaCO3\text{CaCO}_3 precipitate.
  • Sources of error: Leaving the funnel in the burette (titre too low); failing to purge the air bubble from the jet (titre too high).

Mandatory Practical 3: Standardising Sodium Hydroxide

  • Purpose: to find the accurate concentration of approximate NaOH\text{NaOH} using standardised HCl\text{HCl}.
  • Apparatus and Stoichiometry: HCl+NaOH→NaCl+H2O\text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O} (ratio 1:11 : 1).
  • Method:
  1. Pipette 25.0 cm325.0\text{ cm}^3 of approximate NaOH\text{NaOH} solution into a clean conical flask.
  2. Add 2 to 3 drops of methyl orange (solution turns yellow).
  3. Titrate against standard HCl\text{HCl} from the burette until the yellow changes permanently to pink/red.
  4. Obtain concordant titres and calculate the exact concentration of NaOH\text{NaOH}.
  • Safety: Sodium hydroxide is caustic and causes severe chemical burns. Concentrated acids are corrosive. Always wear safety goggles and use a pipette filler; never pipette by mouth.

Titration of an Ammonia Solution

  • Reaction: HCl+NH3→NH4Cl\text{HCl} + \text{NH}_3 \rightarrow \text{NH}_4\text{Cl} (ratio 1:11 : 1).
  • Apparatus: Burette contains standard HCl\text{HCl}; conical flask contains 25.0 cm325.0\text{ cm}^3 of diluted ammonia solution.
  • Indicator: Methyl orange, changing from yellow to pink/red at the end point.
  • Gas testing: Ammonia gas released from concentrated stock turns damp red litmus paper blue and produces dense white fumes of ammonium chloride when brought near a glass rod dipped in concentrated hydrochloric acid.

Mandatory Experiments: Vinegar Analysis and Water of Crystallisation

Mandatory Practical 4: Ethanoic Acid in Vinegar

  • Purpose: to determine the concentration of ethanoic acid in commercial vinegar in mol l−1\text{mol l}^{-1}, g l−1\text{g l}^{-1}, and % (w/v)\%\text{ (w/v)}.
  • Why dilute commercial vinegar: Commercial vinegar is roughly 0.8 to 0.9 mol l−10.8\text{ to }0.9\text{ mol l}^{-1}. Titrating 25.0 cm325.0\text{ cm}^3 directly against 0.100 mol l−1 NaOH0.100\text{ mol l}^{-1}\text{ NaOH} would require well over 200 cm3200\text{ cm}^3 of titrant—more than four full burette fillings, creating compounded measurement errors. Diluting the vinegar brings the required titre into the reliable 15 to 25 cm315\text{ to }25\text{ cm}^3 range.
  • Accurate Dilution Procedure:
  1. Rinse a 10.0 cm310.0\text{ cm}^3 or 25.0 cm325.0\text{ cm}^3 pipette with deionised water and then with commercial vinegar.
  2. Pipette the measured vinegar volume into a clean volumetric flask (50 cm350\text{ cm}^3, 100 cm3100\text{ cm}^3, or 250 cm3250\text{ cm}^3).
  3. Add deionised water with swirling until the level sits just below the graduation mark.
  4. Use a dropper to bring the bottom of the meniscus exactly onto the mark at eye level.
  5. Stopper and invert 20 times to achieve complete mixing.
  6. Dilution factor =Flask volumePipetted volume= \frac{\text{Flask volume}}{\text{Pipetted volume}} (for example, 50.010.0=5\frac{50.0}{10.0} = 5, or 250.025.0=10\frac{250.0}{25.0} = 10).
  • Titration steps: Pipette 25.0 cm325.0\text{ cm}^3 of diluted vinegar into the conical flask, add 2 to 3 drops of phenolphthalein (remains colourless), and titrate with standard NaOH\text{NaOH} from the burette. The end point is reached when a single drop produces a permanent pale pink colour that persists for at least 30 seconds.

Mandatory Practical 5: Water of Crystallisation in Hydrated Sodium Carbonate

  • Purpose: to determine the value of xx in washing soda crystals, Na2CO3⋅xH2O\text{Na}_2\text{CO}_3 \cdot x\text{H}_2\text{O}.
  • Method:
  1. Accurately weigh about 3.5 g3.5\text{ g} of washing soda crystals on a clock glass and dissolve immediately in deionised water, quantitatively transferring into a 250 cm3250\text{ cm}^3 volumetric flask made up to the graduation mark.
  2. Pipette 25.0 cm325.0\text{ cm}^3 into a conical flask, add 2 to 3 drops of methyl orange, and titrate against standard 0.100 mol l−1 HCl0.100\text{ mol l}^{-1}\text{ HCl} from the burette.
  3. End point colour change: yellow to permanent pink/red.
  • Handling precaution: Washing soda crystals are efflorescent. If left exposed to air before weighing, water of crystallisation escapes, leading to an artificially low value for xx.

Thermochemistry of Neutralisation and Heat Calculations

Neutralisation is the chemical reaction between an acid and a base forming a salt and water:

H3O++OH−→2H2OorH++OH−→H2O\text{H}_3\text{O}^+ + \text{OH}^- \rightarrow 2\text{H}_2\text{O} \quad \text{or} \quad \text{H}^+ + \text{OH}^- \rightarrow \text{H}_2\text{O}

Heat of neutralisation is the heat change when one mole of H+\text{H}^+ ions from an acid reacts with one mole of OH−\text{OH}^- ions from a base to form one mole of water, under stated conditions of temperature and pressure. For any strong acid reacting with any strong base, the experimental value is consistently about −57.2 kJ mol−1-57.2\text{ kJ mol}^{-1}. It is identical across all strong acid-base combinations because strong species dissociate completely, reducing the net process purely to hydrogen ions combining with hydroxide ions to form water.

Experimental Calorimetry Procedure

  1. Measure 50.0 cm350.0\text{ cm}^3 of 1.0 mol l−1 HCl1.0\text{ mol l}^{-1}\text{ HCl} into an expanded polystyrene cup using a graduated cylinder or pipette; record its steady temperature.
  2. Measure 50.0 cm350.0\text{ cm}^3 of 1.0 mol l−1 NaOH1.0\text{ mol l}^{-1}\text{ NaOH} into a second container and verify that both solutions are at the identical starting temperature.
  3. Add the NaOH\text{NaOH} solution quickly to the HCl\text{HCl} in the polystyrene cup, replace the lid, stir continuously with a thermometer, and record the highest temperature reached.
  • Why a polystyrene cup: Expanded polystyrene is a thermal insulator with very low heat capacity, minimising heat loss to the surroundings far better than glass.
  • Temperature curve: The temperature rises rapidly because neutralisation is exothermic, reaching a maximum once neutralisation finishes, before slowly declining as heat radiates into the surroundings.

Heat produced is calculated using:

q=m×c×ΔTq = m \times c \times \Delta T

where mm is the total mass of the combined reaction solution in kg\text{kg} (taking 100 cm3≈0.100 kg100\text{ cm}^3 \approx 0.100\text{ kg}), cc is the specific heat capacity (4.18 kJ kg−1 K−14.18\text{ kJ kg}^{-1}\text{ K}^{-1}), and ΔT\Delta T is the temperature increase in K\text{K} or ∘C^\circ\text{C}. The enthalpy change is ΔH=−qmoles of water formed\Delta H = -\frac{q}{\text{moles of water formed}}.

Key terms

Standard Solution
A solution whose concentration is accurately and precisely known.
Primary Standard
A substance that can be obtained in a pure, stable form, of known formula, so that a standard solution can be made by weighing it out accurately and dissolving it in a known volume of water.
Standardisation
The laboratory procedure of determining the exact concentration of a solution by titrating it against a known standard solution.
Equivalence Point
The point during a titration at which stoichiometric amounts of acid and base, as dictated by the balanced equation, have completely reacted.
End Point
The point during a titration at which the indicator changes colour permanently, chosen to coincide with the equivalence point.
Deliquescent
The property of a solid absorbing moisture from the atmosphere until it completely dissolves in the absorbed water.
Efflorescent
The property of hydrated crystals losing their water of crystallisation to the atmosphere when exposed to air.
Conjugate Acid-Base Pair
Two chemical species that differ from each other by the transfer of a single proton.
Heat of Neutralisation
The heat change when one mole of hydrogen ions from an acid reacts with one mole of hydroxide ions from a base to form one mole of water, under stated conditions of temperature and pressure.
Quantitative Transfer
The complete transfer of every particle of a weighed solute into a volumetric flask by washing all contact apparatus with deionised water.

Check yourself

  1. What is the primary rule for selecting a suitable indicator for an acid-base titration?

    The indicator colour-change pH range must lie entirely within the steep, vertical section of the titration curve.

  2. Why can solid sodium hydroxide not be used directly to prepare a primary standard solution?

    Solid sodium hydroxide is deliquescent; it absorbs atmospheric water vapour and dissolves in it, and also reacts with carbon dioxide, preventing accurate weighing.

  3. What is the stoichiometric mole ratio between sodium carbonate and hydrochloric acid in their standardisation reaction?

    1:2 (one mole of Na₂CO₃ reacts with two moles of HCl).

  4. State the colour change of phenolphthalein at the end point when titrating diluted vinegar with sodium hydroxide.

    Colourless to a permanent pale pink that persists for at least 30 seconds.

  5. Why is deionised water used instead of tap water when preparing standard solutions and rinsing glassware?

    Tap water contains dissolved ions and mineral salts that could react with the acid or base, altering the true titre volume.

  6. Explain why the equivalence point pH for a vinegar versus sodium hydroxide titration is above 7.

    The reaction produces sodium ethanoate, a salt of a weak acid and strong base. The ethanoate ion hydrolyses with water to form hydroxide ions, making the solution alkaline.

  7. What is the uncertainty associated with a single burette titre requiring an initial and final reading?

    ±0.1 cm³ (each reading carries an uncertainty of ±0.05 cm³).

  8. State the mathematical expression for the ionic product of water, Kw, and its value at 25 °C.

    Kw = [H₃O⁺][OH⁻] = 1.0 × 10⁻¹⁴ mol² l⁻².

  9. Define heat of neutralisation.

    The heat change when one mole of hydrogen ions from an acid reacts with one mole of hydroxide ions from a base to form one mole of water, under stated conditions of temperature and pressure.

  10. Why is expanded polystyrene used for the reaction vessel during a heat of neutralisation experiment?

    Expanded polystyrene is a thermal insulator with very low heat capacity, minimising heat transfer to the surroundings.

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  3. 3
    Keep revising
    Flashcards and exam-style practice